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w^2-2w-195=0
a = 1; b = -2; c = -195;
Δ = b2-4ac
Δ = -22-4·1·(-195)
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{784}=28$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-28}{2*1}=\frac{-26}{2} =-13 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+28}{2*1}=\frac{30}{2} =15 $
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